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RYD date created : 2025-03-10T10:27:10.090954Z
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Top Comments of this video!! :3
Subject: Request for Rescheduling Ritik Sir’s Maths Class During Ramzan
Dear sir,
I hope you are doing well. I am writing on behalf of several students regarding the timing of Ritik Sir’s mathematics class. Since the holy month of Ramzan has begun, many Muslim students are facing difficulties attending the class at its current schedule due to religious commitments, especially in the late afternoon and evening.
To ensure that every student can participate consistently and make the most of the learning experience, we kindly request that the class be scheduled before 3 PM, if possible. This adjustment would be highly beneficial and greatly appreciated by all students.
We truly appreciate your consideration and support in accommodating everyone's needs. Thank you for your time, and we look forward to your kind response.
Best regards
515 | 66
Sir tbh mere 9th mein aapki wajah se 88 perc aaye the maths mein but 10th allen ki coaching mein papa ne daal diya jiski wajah se mujhe Roz 5 km door jaanapadta tha aur quality study nahi ho paati thi, school, coaching, self study, sleep cycle ud gayi thi. Phir mere maths ke teacher the unho ne bola tha ki main bade hoke chaprasi banoge kuchh nahi kar paoge, maine khud se himmat haar gya tha traumatized ho chuka tha. Kal ki class mein mujhe aapne woh confidence dilaya aur mujhe woh purana Shashwat jo maths aese hi kar deta tha yaad dilaya main aapka bahut shukra guzaar hu 🙏🙏. Mereko laga 10th mein kuchh nahi ho payega par aapne aur alakh sir ne mereko wapas zinda kiya. Thanks Alot sir, kahne ko bahut kahani hai par main tasalli se bata nahi sakta par main bahut demotivated tha sir. Aapne mujhe zinda kardiya. Thank you again🙏🙏. Aapne read Kiya hoga to heart se zarur like kardijiyega taaki main samajh pau mera thank you pahuch gya aap tak.
Thank Y
| 0
Dear pw,
It is my & every muslim student's humble request to you. Please shift maths marathon class timings in morning (from 9 or 10 am) so that every Muslim pwian can attend live class because our holy month "Ramadan" is starting from today (from 2nd March). If live class will be at 6 pm so Muslim students will not be able to attend it as our MAGRIB AAZAAN happens after 6 pm. So please try to understand our situation & problem. It is a humble request to you!
Hoping for an early favorable response from you.
I am a pwian from UDAAN 2025.
Yours sincerely
Sumaiyya!
114 | 14
Given: LCM(a,b)=180,
Ratio between two numbers = 2:3
To find : HCF(a,b)
Let two numbers are 2x and. 3x respectively.
: We know that,
LCM(a,b) ×HCF(a,b) = a×b
LCM= a×b /HCF
180 = 2x × 3x/x. (Since in these two numbers i.e. 2x and 3x the digit x is common so its HCF must be x )
180=6x²/x
180=6x
x= 30
So,
a=2x = 2×30=60
b=3x = 3×30=90
We know that LCM×HCF =a×b
So, 180×HCF =60×90
HCF = 5400/180
HCF(60,90)=30
Answer :30
Thank you Babua and Master ❤❤
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Subject: Request for Morning Classes During Ramzan
Respected Sir,
We hope you are doing well. As the holy month of Ramzan has begun, we, along with many other Muslim students, will be fasting throughout the day. Due to this, attending regular classes in the later hours might be a bit challenging for us.
We humbly request you to consider scheduling our classes in the morning during this month, if possible. This would greatly help us balance both our studies and religious practices. We truly appreciate your understanding and kindness.
Thank you for your time and support.
Sincerely,
(On behalf of Muslim students)
87 | 10
Let two number be 2x and 3x
Let two number be 2x and 3x
LCM= 180
2x.3x=180
x(2X3)=180
x(6)=180
x=180/6
x=30
Therefore the HCF is 30.
15x+15y=240
15(x+y)=240
X+y=16
Possible pair
15+1
14+2
13+3
12+4
11+5
10+6
9+7
8+8
Therefore 4 pairs are possible
Babuaaaaaa Oppppp!
Day 1/7 completed successfully
Confidence level 100% 🔥🔥🔥
Best teacher of maths the “BABUA OP”
Udaan batch ❤️❤️
Diksha Si
| 0
Time stamp 2:44 Q. (For Uday batch) Two no.s are in the ratio 2:3 and their LCM is 180. What is the HCF of these no.s? Sol.) assume that HCF=y And let the two no.s be 2y and 3y Through the formula of, HCF X LCM = PRODUCT OF TWO NO.S y x 180 = 2y x 3y 180 = 6y y= 30 Ans)So therefore HCF will be 30. Explanation:) As like y is the common factor of those two no.s as well as their HCF so the answer would be 30
Sir uday science 😭 please si
1 | 0
Sir Ramzan chal rahe hai 5 baje fast kholna hota hai or fir taraweeh bhi padhni hoti hai usme kam se kam 1½ hour lag jata hai to raat ko 10 baje free ho pate hai sir pdh nhi pate. There are so many of my brothers and sisters who are facing this . Sir please I request you that Luve session 2pm ya 3pm ko rakh lo ya ho sake to subah 10 ya 11 baje ka sirr please😢
33 | 0
Sir here is explanation I hope you will like it 😊 I need batch 😢
I want to become engineer 😊
Solution:
Step 1: Represent the numbers using the given ratio.
* Let the two numbers be 2x and 3x, where 'x' is a common factor.
* Reason: Ratios represent proportional relationships. So, if the ratio is 2:3, it means one number is 2 times a certain value (x), and the other is 3 times the same value (x).
Step 2: Use the relationship between LCM, HCF, and the numbers.
* We know that for any two numbers 'a' and 'b':
* LCM (a, b) × HCF (a, b) = a × b
* Reason: This is a fundamental theorem in number theory. It connects the least common multiple (LCM) and the highest common factor (HCF) of two numbers with the product of those numbers.
Step 3: Apply the formula with the given values and expressions.
* We are given that LCM (2x, 3x) = 180.
* So, 180 × HCF (2x, 3x) = (2x) × (3x)
* 180 × HCF (2x, 3x) = 6x²
* Reason: We are substituting the given LCM and the expressions for our two numbers (2x and 3x) into the formula.
Step 4: Find the LCM of 2x and 3x.
* The LCM of 2x and 3x is 6x.
* Reason: Since 2 and 3 are prime numbers, their least common multiple is their product (2 × 3 = 6). The 'x' is a common factor, so it must also be included in the LCM.
Step 5: Use the given LCM to find the value of x.
* We are given that the LCM is 180, and we found the LCM to be 6x.
* Therefore, 6x = 180.
* x = 180 / 6
* x = 30
* Reason: By equating the calculated LCM (6x) with the given LCM (180), we can solve for the unknown value 'x'.
Step 6: Determine the two numbers.
* The numbers are 2x and 3x.
* 2x = 2 × 30 = 60
* 3x = 3 × 30 = 90
* Reason: Now that we know the value of 'x', we can substitute it back into the expressions for our two numbers.
Step 7: Find the HCF of 60 and 90.
* We can use the formula again:
* LCM (60, 90) × HCF (60, 90) = 60 × 90
* 180 × HCF (60, 90) = 5400
* HCF (60, 90) = 5400 / 180
* HCF (60, 90) = 30
* Alternatively, we know that the HCF of 2x and 3x is x, because 2 and 3 are prime.
* Therefore the HCF = 30.
* Reason: We use the same formula to calculate the HCF. We also remember that since the numbers were 2x and 3x, and we know x, the HCF is x.
Answer: The HCF of the two numbers is 30.
❤ I hope I was able to explain you
Pw is ❤
If you want to contact me so here is my insta id aman_yadav_927
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@aashidrawing1415
2 months ago
Good morning babua ❤
Day 1 me maza aa gya
Ab day 2 ki baari
740 | 9